問題描述
我的目標是保持 UIPopoverController 的坐標相同，只需更改箭頭偏移量.所以基本上我有三個按鈕觸摸它們中的每一個都會顯示一個彈出窗口.呈現此彈出框時，它會更改屏幕上的位置，但我不希望那樣.為了更清楚地查看屏幕截圖:
My goal is to keep same coordinates for a UIPopoverController with just changing arrow offset. So basically i have three buttons touching each of them shows up a popover. When presenting this popover it changes position on the screen, but i do not want that. To be more clear look at screenoshots:
推薦答案
對于我的彈出框，我希望箭頭位于左上角而不是頂部居中(這是默認設置).
For my popover I wanted the arrow to be top-left instead of top-center (which is default).
通過設置 UIPopoverController 的 popoverLayoutMargins 屬性，我設法得到了下面的結果(屏幕截圖).您可以使用它來減少 UIPopoverController 內部計算中使用的屏幕區(qū)域，以確定在何處顯示彈出框.
I've managed to get the result below (screenshot) by setting the popoverLayoutMargins property of the UIPopoverController. You can use it to reduce the screen-area used in the internal calculations of the UIPopoverController to determine where to show the popover.
代碼:
// Get the location and size of the control (button that says "Drinks")
CGRect rect = control.frame;
// Set the width to 1, this will put the anchorpoint on the left side
// of the control
rect.size.width = 1;
// Reduce the available screen for the popover by creating a left margin
// The popover controller will assume that left side of the screen starts
// at rect.origin.x
popoverC.popoverLayoutMargins = UIEdgeInsetsMake(0, rect.origin.x, 0, 0);
// Simply present the popover (force arrow direction up)
[popoverC presentPopoverFromRect:rect inView:self.view permittedArrowDirections:UIPopoverArrowDirectionUp animated:YES];
我認為您可以通過調整上述內容來獲得所需的結果.
I think you'll be able to get the desired result by tweaking the above.
這篇關于將 UIPopoverController 呈現在相同位置，僅更改箭頭偏移量的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！