問題描述

我正在嘗試使用以下代碼將地址地理編碼為坐標:

I am trying to geocode address into coordinates using following code:

CLGeocoder *geocoder = [[CLGeocoder alloc] init];
    [geocoder geocodeAddressString:@"6138 Bollinger Road, San Jose, United States" completionHandler:^(NSArray* placemarks, NSError* error){
                     for (CLPlacemark* aPlacemark in placemarks)
                     {
                         // Process the placemark.
                         NSString *latDest1 = [NSString stringWithFormat:@"%.4f",aPlacemark.location.coordinate.latitude];
                         NSString *lngDest1 = [NSString stringWithFormat:@"%.4f",aPlacemark.location.coordinate.longitude];
                         lblDestinationLat.text = latDest1;
                         lblDestinationLng.text = lngDest1;
                     }
                 }];

我已經嘗試了很多次，但調試器從不進入塊，我無法獲得位置.有人可以幫我嗎?

I have tried it many times but the debugger never enters the block and I am not able to get the location. Can someone please help me with it?

問候
潘卡伊

推薦答案

好吧，我發現我的錯誤了.代碼是正確的并且工作完美.我一直在通過調試器處理它，并試圖找出調試器沒有進入塊的原因.但是現在我發現調試器此時沒有進入該塊.獲取位置值所需的時間很少.它是異步完成的，因此我無法找到它，并且由于崩潰后沒有值而導致崩潰.我已將代碼發布塊移到塊內，現在一切正常.

All right I found my mistake. The code is correct and works perfect. All the while I was working on it was through debugger and was trying to figure out why the debugger did not enter the block. But now I have found out debugger does not enter the block at that moment. It takes little in getting the location values. It is done asynchronously so I was not able to find it and I was getting crash because of no values just after the crash. I have moved my code post block to inside the block and everything works fine for me now.

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