問(wèn)題描述

我必須經(jīng)常在兩種布局之間切換.錯(cuò)誤發(fā)生在下面發(fā)布的布局中.

I have to switch between two layouts frequently. The error is happening in the layout posted below.

當(dāng)我的布局第一次被調(diào)用時(shí)，沒(méi)有發(fā)生任何錯(cuò)誤，一切都很好.然后當(dāng)我調(diào)用不同的布局(空白的)然后再次調(diào)用我的布局時(shí)，它會(huì)引發(fā)以下錯(cuò)誤:

When my layout is called the first time, there doesn't occur any error and everything's fine. When I then call a different layout (a blank one) and afterwards call my layout a second time, it throws the following error:

> FATAL EXCEPTION: main
>     java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

我的布局代碼如下所示:

My layout-code looks like this:

    tv = new TextView(getApplicationContext()); // are initialized somewhere else
    et = new EditText(getApplicationContext()); // in the code


private void ConsoleWindow(){
        runOnUiThread(new Runnable(){

     @Override
     public void run(){

        // MY LAYOUT:
        setContentView(R.layout.activity_console);
        // LINEAR LAYOUT
        LinearLayout layout=new LinearLayout(getApplicationContext());
        layout.setOrientation(LinearLayout.VERTICAL);
        setContentView(layout);

        // TEXTVIEW
        layout.addView(tv); //  <==========  ERROR IN THIS LINE DURING 2ND RUN
        // EDITTEXT
        et.setHint("Enter Command");
        layout.addView(et);
        }
    }
}

我知道以前有人問(wèn)過(guò)這個(gè)問(wèn)題，但對(duì)我的情況沒(méi)有幫助.

I know this question has been asked before, but it didn't help in my case.

推薦答案

錯(cuò)誤信息說(shuō)明了你應(yīng)該做什么.

The error message says what You should do.

// TEXTVIEW
if(tv.getParent() != null) {
    ((ViewGroup)tv.getParent()).removeView(tv); // <- fix
}
layout.addView(tv); //  <==========  ERROR IN THIS LINE DURING 2ND RUN
// EDITTEXT

這篇關(guān)于指定的孩子已經(jīng)有一個(gè)父母.您必須首先在孩子的父母上調(diào)用 removeView() (Android)的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！